Numerical
1. calculate uncertainty in velocity of an electron if uncertainty in position is 1Angstrom given mass of electron 9.1× 10^-34kgm^2s^-1.
sol.
∆x = 10^-10m
mass of electron = 9.1×10^-31kg
h =6.6×10^-34kg m^2s^-1
∆V=?
we know ∆x.∆p=h/4π
∆xm∆V =h/4π because p=mv
or ∆V= h/(4π×m×∆x)
putting all values we get
∆V= 5.77×10^5m/s ans
2. calculate uncertainty in position of electron if uncertainty in velocity is 0.0001℅ given
velocity of electron = 300m/s.
sol.
∆x =?
∆v= 0.0001℅×300
= (0.0001/100) ×300= 3×10^-4m/s
mass of electron = 9.1×10^-31kg
h =6.6×10^-34kg m^2s^-1
we know ∆x.∆p= h/4π
∆x.m.∆V= h/4π
∆x= h/(4π.m.∆V)
putting all value we get
∆x= 1.92×10^ -3metre ans
1. calculate uncertainty in velocity of an electron if uncertainty in position is 1Angstrom given mass of electron 9.1× 10^-34kgm^2s^-1.
sol.
∆x = 10^-10m
mass of electron = 9.1×10^-31kg
h =6.6×10^-34kg m^2s^-1
∆V=?
we know ∆x.∆p=h/4π
∆xm∆V =h/4π because p=mv
or ∆V= h/(4π×m×∆x)
putting all values we get
∆V= 5.77×10^5m/s ans
2. calculate uncertainty in position of electron if uncertainty in velocity is 0.0001℅ given
velocity of electron = 300m/s.
sol.
∆x =?
∆v= 0.0001℅×300
= (0.0001/100) ×300= 3×10^-4m/s
mass of electron = 9.1×10^-31kg
h =6.6×10^-34kg m^2s^-1
we know ∆x.∆p= h/4π
∆x.m.∆V= h/4π
∆x= h/(4π.m.∆V)
putting all value we get
∆x= 1.92×10^ -3metre ans
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