Shape of compounds due hybridisation

Shape of compounds due hybridisation

1.Shape of IF7 ( iodine hepta fluoride)
Ground state
I
(53)    5s^2 5px^2 5py^2 5pz^1 5d^0
excited state
           5s^1 5px^1 5py^1 5pz^1 5d^3
             {     sp3d3 hybridisation          }

since sp3d3 hybridisation takes place .so IF7 molecule is pentagonal bipyramidal.

bond angles 72° &  90°.

2.shape of NH3(Ammonia)
Ground state
N
(7)   1s^2 2s^2 2px^1 2py^1 2pz^1
         {sp3 hybridisation}
since sp3 hybridisation takes place. so NH3 molecule should be tetrahedral. but actual NH3 molecule pyramidal. because one position of tetrahedral occupied by lone pair of electron.

Due to lone pair -bond pair repulsion bond angle decrease from 109°28'

3.shape of H2O(Water)
Ground state
(H)  1s^2 2s^2 2px^2 2py^1 2pz^1
               { sp3 hybridisation}
since sp3 hybridisation takes place so H2O molecule should be tetrahedral is V shaped (bent shaped)  because two positions of tetrahedral are occupied by lone pair of electron.

4.Shape of SF4(sulphur tetrahedral fluoride)
Ground state
S
(16)   3s^2  3px^2 3py^1 3pz^1 3d^0
excited state
        3s^2  3px^1 3py^1 3pz^1 3d^1
                      {sp3d hybridisation}
since sp3d hybridisation takes place. so SF4 molecule should be triangular Bipyramidal. but actually SF4 molecule has Distorted triaginal bipyramidal structure.