shape of compounds due hybridisation

shape of compounds due hybridisation
1.Shape of sncl2 (stannois chloride)
Ground state
Sn
(50)  5s^2 5px^1 5py^1 5pz^0
since sp^2 hybridisation takes place so sncl2 molecule should be triangular or triginal planar but actually sncl2 molecule is Bent because ane position of triangle is occupied by lone pair of electron.

2 shape of ClO4(perchlorate)
Ground state
Cl
(17)   3s^2 3px^2 3py^2 3pz^1 3d^0
excited state
          3s^2 3px^1 3py^1 3pz^1   3d^3
           { sp3 hybridisation }      {π bond}

orbital formed π bond don't take part in hybridisation .since sp3 hybridisation take place . so ClO4 is tetrahedral.

3.Shape of ClO3^-(chlorate ion)
Ground state
Cl
(17)  3s^2  3px^2 3py^2 3pz^1 3d^0
excited state
          3s^2  3px^1 3py^1 3pz^1 3d^2
          { sp3 hybridisation}    {2π bond}
since sp3 hybridisation takes place .so clo3^-should be tetrahedral. but actually clo3^-
is pyramidal .because one position of tetrahedral occupied by lone pair of electron.

4.Shape of So4^2-(sulphate ion)
ground state
S
(16)     3s^2  3px^2 3py^1 3pz^1 3d^0
excited state
             3s^1  3px^1 3py^1 3pz^1 3d^2
               (sp3 hybridisation)   (2πbond)
since sp3 hybridisation takes place. so   So4^2-
is tetrahedral.

5.Shape of No3^-(nitrate ion)
ground state
N
(7)    1s^2  2s^2 2px^1 2py^1    3pz^1
                  ( sp hybridisation)   ( form c-o-b)
since sp^2 hybridisation takes place NO3^- is triangular planar.  bond angle 120°

6.Shape of Icl2^-(Inter halogen)
ground state
I
(53)    5s^2  5px^2 5py^2 5pz^1    5d^0
            {sp3d hybridisation}  ( form c-o-b)
since sp3d hybridisation takes place so Icl2^- ion should be trigonal bypyramidal but  actually Icl2^- is linear. because three positions of triangle occupied by lone pair of electron.

Direct Determine Hybridisation

formula
1/2[V+X-C+A]
here
V- no. of electron in valence shell of                       central atom.
X-no.  of monovalent atom
C- charge on cation(+)
A- charge on anion(-)