Skip to main content

Important question related to ionisation energy

Important question related to ionisation energy: 

Question 1
Ionisation energy of gases is higher. why?

ans.  because of higher stable of ns^2 np^6 configuration.

or

noble gases have completely filled valence shell  whuchbis more stable. so removal of electron is very difficult. hence I. E of noble gases is high.

Question 2
which have more ionisation energy Oxygen & nitrogen?

ans
O
(8)    1s^2  2s^2  2p^4

N
(7)    1s^2  2s^2  2p^3


Nitrogen has exactly half filled p subshell .whuch is more stable as a result removal electron becomes difficult. hence I. E of nitrogen is more than oxygen.

hence peaks show half filled & completely filled subshell of atom .which  required more energy for removal of electron .hence I. E is more

Question 3
First I. E of aluminum is less than magnesium. why?

ans
Al
(13) 1s^2  2s^2  2p^6  3s^2 3p^1

Mg
(12) 1s^2  2s^2  2p^6  3s^2

in aluminum we have to remove electron from 3p orbital  which required comparatively less energy .hence first I. E of aluminum is less than magnesium.


Question 4
First I. E of magnesium is higher than that of aluminum .while 2nd I. E of sodium is higher than Magnesium.

ans

Mg
(12) 1s^2  2s^2  2p^6  3s^2

Al
(13) 1s^2  2s^2  2p^6  3s^2 3p^1

in Mg  when  first electron remove its remove from the s subshell which highly stable. so we required large amount of energy to remove electron from Mg as compare to Al. so I. E(1)   is more than Aluminum of magnesium


Mg^+
(12) 1s^2  2s^2  2p^6  3s^1

Al ^+
(13) 1s^2  2s^2  2p^6  3s^2

when I. E(2)  is removed than aluminum taken more energy as compare to magnesium. so we can say that I. E(2)  of Aluminium is more than magnesium

similarly
Question 5
 I. E(1)  of magnesium is higher than that of Na while I. E(2)  of Na is higher than Mg. 

Question 6 
First ionisation energy of alkaline earth metal is low and second is higher but show deviated state (+2) ?

ans
 because hydration energy of group 2 element is large. so at The I. E(2)  when electron remove is attain more energy. so I. E (2)  is more due to hydration energy. 






Comments

Popular posts from this blog

Radial probability distribution for p and d orbital, radial wave functions

Radial probability distribution for p and d orbital Radial and Angular wave function:  the radial part of wave function depends upon quantum no.  n and  l  and gives the distribution of electron w. r. t distance .it is governed mainly exponential term     e^-Zr/na°(a not)   here  e   based on natural log.  Z   Atomic number r     distance from nucleus  n    principal quantum no. or radial quantum           no.  a°    0.529A° for hydrogen  ( Bohr radii)  the exact mathematical expression for radial part of wave function for 1s or 2s and 2p orbitals. n= 1 ,l=0 s orbital    R(r) =2× (z/a°) ^3/2 ×(2-zr/a°) ×e^-zr/2a° n= 2 ,l=0 2s orbital    R(r) = (z/a°) ^3/2 ×(2-zr/a°) ×e^-zr/2a° n= 2 ,l=1 2p orbital    R(r) = 1√3×(z/2a°) ^3/2 ×(zr/a°) ×e^-zr/2a ° the radial wave function can be represented by plotting radial function R(r)  apart distance(r)

Physical significance of sie and sie^2

Physical significance of sie and sie^2  The wave function sie has no physical significance,  it simply represents amplitude of wave   while square of amplitude sie^2 represent intensity of electron.  i. e sie ^2 gives probability of finding the electron in space .p the space is called atomic orbital  A zero value of sie^2 means probability of finding the electron is zero and high value of sie^2 means greater chances of finding the electron .  the value of sie^2 lies between 0&1. if sie^2 =1   100℅  sie^2=0    0℅

Linear combination of atomic orbital, Molecular orbital theory, Difference between bonding & anti bonding moleculer orbital.

Linea combination of atomic orbital  molecular orbital are formed by combination of atomic orbital  if ꌏ(A)  andꌏ(B)  are the wave function of atomic orbital of two combining atomic A and B  then according  to Linea combination of atomic orbital, these two wave function can be added or can be substracted .that means there are two modes of interaction (symmetric and antisymmetric)  We know ꌏ(s)  = ꌏ(A) +ꌏ(B)  ꌏ(a) = ꌏ(A)- ꌏ(B) ꌏ(s)  and ꌏ(a)  represent wave function of bonding and antibonding moleculer orbital. the formation of moleculer orbital ꌏ(s)  and ꌏ(a)  from two atomic orbital ꌏ(A) and ꌏ(B)  is represented as Molecular orbital theory (MO)  theory: main points of mo theory are: 1.whwn atomic orbital combine they formed molecular orbital. 2.Number of molecular orbital formed is equal to number of atomic orbital combine. 3.atomic orbital are uninuclear  while molecular orbital  are polynuclear. 4.The various molecular orbital are arranged in order of in increas