Skip to main content

shapes of many compounds due hybridisation

shapes of many compounds due hyberdisation

1.shape of BF3 (boron trifluoride)

Ground state
 B
(5)    1s^2  2s^2  2px^1  2py^0 2pz^0

excited state

    1s^2  2s^1  2px^1  2py^1  2pz^0
                { sp2 hybridisation}
since sp2 hybridisation takes place. so BF3 molecule triangular with bond angle 120°
triangular or trigonal planer

2.shape of CH4 (Methane)

Ground state
 C
(5)    1s^2  2s^2  2px^1  2py^1 2pz^0

excited state

    1s^2  2s^1  2px^1  2py^1  2pz^1
                { sp3  hybridisation}
since sp3 hybridisation takes place. so CH4 molecule tetrahedral with bond angle 109°.28'

3. shape of PF5 (phosphorus pentafluorine)

Ground state
 P
(15)    3s^2  3px^1  3py^1 3pz^1 3d^0

excited state

          3s^2  3px^1  3py^1  3pz^1  3d^1
                      { sp3d hybridisation}
since sp3d hybridisation takes place. so PF5 molecule is tringonal bipyramidal.

equitorial 120°
axial 90°
axial bond are slightly larger than equatorial bond because axial bond forces greater repulsion than equitorial. so PF5 is quite reactive.

6.shape of SF6 (sulphur hexafluoride)

Ground state
 S
(16)   3s^2  3px^2  3py^1 3pz^1 3d^0

excited state

          3s^2  3px^1  3py^1  3pz^1  3d^2
                      { sp3d2 hybridisation}
since sp3d hybridisation takes place. so SF6 molecule is Octahedral with  all bond angle 90°.

so SF6 is no reactive

Comments

Popular posts from this blog

Radial probability distribution curves

Radial probhjjhajajbability distribution curves:  The probability of finding the electron is given by the quantity  sie^2.By radial probability us probability of finding the electron within small Radial space around the nucleus. volume of spherical shell between radius r and r+dr =4πr^2 and probability of finding the electron will be 4πr^2dr sie^2. radial probability distribution curves are obtained by plotting radial probability at various distance from the nucleus . 1.Radial probability distribution curves for S orbital n=1, l= 0. distance from nucleus here A° is called angstrom. the probability of finding of electron in a shell is maximum at distance r=r° (r not)  which is 0.529 A° for H atom. diagram shows that probability plot for 2s has(two region of high probability)  or (two peaks)  separated by node. we conclude that  no.  of high probability region in S orbital = n no.  of node = ( n-1) 

Radial probability distribution for p and d orbital, radial wave functions

Radial probability distribution for p and d orbital Radial and Angular wave function:  the radial part of wave function depends upon quantum no.  n and  l  and gives the distribution of electron w. r. t distance .it is governed mainly exponential term     e^-Zr/na°(a not)   here  e   based on natural log.  Z   Atomic number r     distance from nucleus  n    principal quantum no. or radial quantum           no.  a°    0.529A° for hydrogen  ( Bohr radii)  the exact mathematical expression for radial part of wave function for 1s or 2s and 2p orbitals. n= 1 ,l=0 s orbital    R(r) =2× (z/a°) ^3/2 ×(2-zr/a°) ×e^-zr/2a° n= 2 ,l=0 2s orbital    R(r) = (z/a°) ^3/2 ×(2-zr/a°) ×e^-zr/2a° n= 2 ,l=1 2p orbital    R(r) = 1√3×(z/2a°) ^3/2 ×(zr/a°) ×e^-zr/2a ° the rad...

Electronegativity scales and disadvantage of scales and its nunericals

Electronegativity scales: 1.Pauling scale of electronegativity: in diatomic molecule (A-B) ,the bond formed between two atoms A and  B will be intermediate between  pure Covalent (A-B)  and pure ionic character,  the bond between A and B will be  strong than bond energy increased. if bond (A-B) has been purily covalent than bond energy can be calculated as average bond energy of bond (A-A)  and bond (B-B).     that means it is equal to bond energy of bond (A-B) E(A-B)  = 1/2[ E(A-A) +E(B-B) ] however experiemental value of bond (A-B)  more than this value  because of difference in electronegativity  of A and B the difference ∆ is given by simple expression ∆ = E(A-B) - 1/2 [E(A-A) +E(B-B) ] where E(A-B)  is experimental value of bond energy. if Ҳ(A)  and  Ҳ(B) are the electronegative of elements A and B than Ҳ(A) - Ҳ(B) = 0.18√∆ for numerical ∆ = E(A-B)  -[√(E(A-A) ×E(B-B) )] Disadvan...